Timeline for What happens when I use a conjugate gradient solver with a symmetric positive semi-definite matrix?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Jul 1 at 12:23 | history | suggested | Royi | CC BY-SA 4.0 |
Added a link description
|
| Jul 1 at 7:16 | review | Suggested edits | |||
| S Jul 1 at 12:23 | |||||
| Apr 10, 2023 at 7:58 | comment | added | Federico Poloni | @syockit This does not sound immediate to prove to me at the moment (but I might be just missing things, I did not think thoroughly about this issue). If $b_2$ is not zero, all iterates $x_k$ of CG have a nonzero second block $(x_k)_2$, and this block may change the scalar products and affect the convergence behavior of CG. | |
| Apr 10, 2023 at 5:58 | comment | added | syockit | If it's not orthogonal to the kernel, the residual of $b-Ax$ simply converges to the component of $b$ spanned by the kernel, right? | |
| May 28, 2020 at 11:03 | vote | accept | allo | ||
| May 28, 2020 at 10:28 | history | edited | Federico Poloni | CC BY-SA 4.0 |
added 130 characters in body
|
| May 28, 2020 at 9:24 | history | answered | Federico Poloni | CC BY-SA 4.0 |