Timeline for About the condition $\ker(B_h) \subset \ker(B)$ in mixed finite elements formulation
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| S Jul 31, 2021 at 9:04 | history | bounty ended | CommunityBot | ||
| S Jul 31, 2021 at 9:04 | history | notice removed | CommunityBot | ||
| S Jul 23, 2021 at 8:00 | history | bounty started | FEGirl | ||
| S Jul 23, 2021 at 8:00 | history | notice added | FEGirl | Canonical answer required | |
| Jul 22, 2021 at 0:00 | history | tweeted | twitter.com/StackSciComp/status/1417997852899520513 | ||
| Jul 21, 2021 at 12:50 | history | edited | FEGirl | CC BY-SA 4.0 |
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| Jul 21, 2021 at 12:38 | history | edited | FEGirl | CC BY-SA 4.0 |
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| Jul 21, 2021 at 10:39 | comment | added | FEGirl | @Jan I edited the question, maybe now it's more clear. Basically, he said that the condition on the kernels implies that the diagram commutes. It seems to be trivial, but I really don't see how | |
| Jul 21, 2021 at 10:38 | history | edited | FEGirl | CC BY-SA 4.0 |
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| Jul 21, 2021 at 10:03 | comment | added | Jan | Nice question -- but I don't understand this either. What does it mean this arrow exists. Maybe that $B_h$ together with $V_h$ and $Q_h$ fulfill an inf-sup condition with a constant independent of $h$? (That would be the standard requirement for inf-sup stable finite elements) | |
| Jul 21, 2021 at 7:51 | history | asked | FEGirl | CC BY-SA 4.0 |