I want to maximise the score of the following table, choosing one item from each column/row, so no two items are on the same row or column. Score to maximise is just adding all the choices together.
$$*\quad A\quad B\quad C\quad D\quad E$$ $$\alpha\quad 16\quad 16\quad 18\quad 18\quad 18$$ $$\beta\quad 20\quad 18\quad 16\quad 12\quad 10$$ $$\gamma\quad 20\quad 18\quad 18\quad 16\quad 16$$ $$\delta\quad 18\quad 18\quad 16\quad 16\quad 8$$ $$\epsilon\quad 10\quad 12\quad 14\quad 14\quad 14$$
Example: ($^{C}$ means chosen)
$$*\quad A\quad B\quad C\quad D\quad E$$ $$\alpha\quad 16^{C}\quad 16\quad 18\quad 18\quad 18$$ $$\beta\quad 20\quad 18\quad 16\quad 12\quad 10^{C}$$ $$\gamma\quad 20\quad 18^{C}\quad 18\quad 16\quad 16$$ $$\delta\quad 18\quad 18\quad 16^{C}\quad 16\quad 8$$ $$\epsilon\quad 10\quad 12\quad 14\quad 14^{C}\quad 14$$
Gives a score of $16+10+18+16+14=74$
Now there are a few ways to do this, but can firstly, someone actually tell me if $88$ really is the best result and how can this be done computational. Note: I am a Mathematics student and would normally approach such a problem with graph theory, but would like to see computation methods.