Calculating lagrange polynomial for 100 points?

Question

I need to calculate the lagrange polynomial which approximates $e^x$ at $101$ points, the points $\frac{k}{101^2}$ for $k\in\{0,1,2\dots 100\}$.

I tried the following code:

import java.math.*;
import org.apache.commons.math3.analysis.polynomials.PolynomialFunctionLagrangeForm;

public class interpolation {


    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int N = 100;

        double [] X = new double [N+1];
        double [] Y = new double [N+1];

        // Here we give the computer the points:

        for(int k=0; k<=N ;k++){
            double a = k/(N*N*1.0);
            double b = Math.exp(a);
            X[k]=a;
            Y[k]=b;
        }

        // here we build the polynomial

         PolynomialFunctionLagrangeForm pol = new PolynomialFunctionLagrangeForm( X , Y );

         double [] P = pol.getCoefficients();

         // here we print the polynomial

         for(int i=P.length -1 ;i >= 0;i--){
             System.out.print( P[i] + "    ");
         }


    }

}

It gives good results for $N=5,10$ but bad ones for $N=50,100$ (it doesn't resemble the Taylor expansion at all). I would like help in calculating this polynomial more precisely. Thank you kindly.