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Consider we have a linear bivariate polynomial: $$p(x,y)=ax+by+c.$$

To construct the linear polynomial using least square method, we need to evaluate the value of the average polynomial $p$ in at least in three cells that approximately must be equal to the average of conservative variable $\bar{\psi}$. $$\frac{1}{\Delta_i}\int_{\Delta_i}{p(x,y)}\,dx\,dy = \bar{\psi}_i.$$

My question are:

  1. How should I define the limit of integration?
  2. How to evaluate the integral of the polynomial?
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If $(x_i,y_i)$ is the centroid of the triangle, then $$ \frac{1}{\Delta_i}\int_{\Delta_i}{p(x,y)}\,dx\,dy = p(x_i,y_i) = \bar{\psi}_i $$ This is mid-point quadrature, which is exact for an affine function. The centroid of a triangle is the arithmetic average of its three vertices. Note that $$ x_i = \frac{1}{\Delta_i} \int_{\Delta_i} x dx dy = \frac{1}{3}\sum_{vert} x_{vert} $$ and similarly for $y_i$. This suggests to reparametrize $p$ as $$ p = \bar{\psi}_i + a (x-x_i) + b(y-y_i) $$ which automatically satisfies the average condition.

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  • $\begingroup$ Is your answer valid for arbitrary triangle? $\endgroup$
    – Lele Mabur
    Nov 9 '20 at 7:48
  • $\begingroup$ yes, it is valid. $\endgroup$
    – cfdlab
    Nov 9 '20 at 9:31
  • $\begingroup$ Sorry I just noticed from your answer that the quadrature is exact for an affine function, how if the function is quadratic? $\endgroup$
    – Lele Mabur
    Nov 9 '20 at 9:57

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