New answers tagged ode
0
Looking at the code, unless there is something weird under the hood, it is semi-implicit Euler.
I do not know any integration/differentiation technique called Newton-Euler. From what I read, it is a formulation to describe motion and a competitor to Lagrangian formulation. The book might be talking about the particular forms first and second order explicit ...
3
Well, in answer to the question about the use of higher-order RK methods, I have a few things to add to the discussion:
As an example, it is often helpful to plot an "efficiency diagram" for several different methods being applied to a given initial value problem (using a variety of stepsizes). On such a diagram, one can plot (for each method) how the ...
2
Due to your formulation, I call $X(z) = \begin{bmatrix}
x(z) \\
p_{x}(z)
\end{bmatrix}$ so your ODE is written in matrix form:
$$X^{'}(z) = C(z) X(z)$$
Where: $C(z) = \begin{bmatrix}
0 & A(z) \\
B(z) & 0
\end{bmatrix}$.
Your general formula by using backward Euler method is:
$$\frac{X(z+\Delta z) - X(z)}{\Delta z} = C(z+\Delta z) X(z+\Delta z)$$
...
4
Parareal is fairly effective for parabolic problems, but doesn't work well for hyperbolic problems. So it wouldn't be effective for the advection part, but could be effective for the diffusion part. Making it work well for hyperbolic problems is an area of ongoing research. Note that the parallel efficiency of parareal is quite poor, so if you haven't yet ...
2
The phenomenon you're dealing with here is called a "stiff system". Check here for a full explanation: http://www.scholarpedia.org/article/Stiff_systems
Matlab’s ode45 is a non-stiff solver, thus ill-suited for your problem. You should try to use one stiff solver. Matlab has 4 stiff solvers but other tools like Scipy’s solve_ivp also possess non-stiff ...
3
I would recommend 3 things to pursue:
Use ode15s (a stiff solver). This will allow for better resolution near the jumps
Rescale the problem. Your coefficients are very large and if they are changing by several orders of magnitude, this is likely causing undue conditioning problems with your solver so rescaling then undoing the scaling after the ode solve is ...
1
To give a short summary of the answer of @Gabriele, the main point is that in a numerical solution of a second order system $x''=f(x)$ as you have with a first order solver as RK4, you need to transform the problem into a first order system
$$
x'=p,\\
p'=f(x).
$$
This is also the point of departure of the question, it is only in the implementation that the ...
5
The first step is to transform the second order equation to a set of two coupled first order equations. Define an auxiliary function $u(T) = \frac{dr(T)}{dT}$. This results in the system
$$\begin{align}
\frac{du}{dT} &= k-(1-\frac{5}{r})(3+\frac{2}{r^2}) \\
\frac{dr}{dT} &= u\\
\frac{d\phi}{dT} & = \frac{1}{r^2}
\end{align}
$$
Now you have a ...
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