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Sep 17, 2018 at 16:36 comment added Msegade @BillGreene But I want vibration modes that take damping into consideration. With traditional modes I get an eigenvector that I can represent (say for example (1, -1) in a 2DOF system. With complex eigenvectors it gives something like (1+2j, 0.5 -1j) which I cannot represent. I'm looking for a way to make sense of this eigenvectors by transforming them into real modes.
Sep 15, 2018 at 20:31 answer added Chris timeline score: 1
Sep 13, 2018 at 18:59 comment added Bill Greene You can't "convert" complex eigenvectors to real. The eigenvectors are complex because you have damping in your model. If you want to calculate traditional vibration modes for this model, set the damping matrix to zero.
Sep 13, 2018 at 16:57 comment added nicoguaro Even in the linear eigenvalue problem you (might) have complex eigenvectors.
Sep 13, 2018 at 16:24 comment added Msegade @nicoguaro Yes, but that gives complex eigenvectors, I'm talking of a way of transforming those into real ones.
Sep 13, 2018 at 14:49 comment added nicoguaro "We can then take the first $n$ components of $z$ as the eigenvector $x$ of the original quadratic $Q ( λ )$" from Wikipedia
Sep 13, 2018 at 10:05 history asked Msegade CC BY-SA 4.0