Timeline for Runge-Kutta when time dependence not known
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 14, 2018 at 23:40 | history | migrated | from stackoverflow.com (revisions) | ||
| Sep 14, 2018 at 1:46 | vote | accept | CommunityBot | ||
| Sep 13, 2018 at 6:41 | comment | added | Lutz Lehmann | @WindowsNT: Yes, exactly that, you understood the answer correctly. | |
| Sep 12, 2018 at 22:53 | comment | added | WindowsNT | So, since f(t, y)=-y/tau I can say that f(t+h/2, y+k1 / 2) is just -( y+ k1 / 2 )/ tau? I was thinking that since y was a function of t that I would have to do -( y(t+h /2)+ k1 / 2 )/ tau. Am I supposed to ignore that y is a function of t for the function f(t, y)? That's what your answer seems to say. | |
| Sep 12, 2018 at 22:14 | history | answered | gnasher729 | CC BY-SA 4.0 |