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Jul 10, 2022 at 23:16 comment added Wolfgang Bangerth No, there are also terms that relate to the boundary values $g$. I updated the answer accordingly.
Jul 10, 2022 at 23:15 history edited Wolfgang Bangerth CC BY-SA 4.0
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Jul 9, 2022 at 16:29 comment added vibe In order for the $A_i$ to be non-trivial, it seems required that $f \neq 0$. So does this mean that this method will not work for the Laplace equation, where $f = 0$?
Jul 9, 2022 at 1:52 comment added Wolfgang Bangerth That's right -- the eigenfunctions are simply the functions associated with the eigenvectors of the discretized operator.
Jul 8, 2022 at 22:41 comment added nicoguaro @vibe, there are several answers within this site for that. See for example this one
Jul 8, 2022 at 19:01 comment added vibe Thank you for your comment. Do you know of any references, example code, etc which show how to actually perform the steps in Theorem 3?
Jul 8, 2022 at 17:01 history answered Wolfgang Bangerth CC BY-SA 4.0