Timeline for Method to compute $a^n - b^n$
Current License: CC BY-SA 4.0
3 events
| when toggle format | what | by | license | comment | |
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| Jan 14, 2023 at 7:09 | comment | added | Oscar Smith | that will teach me to not answer these at 2am on a phone :) | |
| Jan 14, 2023 at 7:06 | comment | added | Lutz Lehmann |
This is wrong. It should be -a^n*expm1(n*log1p((b-a)/a)). In the example this gives 7.526705395707148e+24, which is close to the exact result in the limitations of floating-point numbers.
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| Jan 14, 2023 at 6:59 | history | answered | Oscar Smith | CC BY-SA 4.0 |