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Jan 23, 2013 at 4:55 history tweeted twitter.com/#!/StackSciComp/status/293944904109928449
Jan 22, 2013 at 18:54 comment added BRabbit27 Sorry, I meant parabolic. (I was reading something about hyperbolic problems).
Jan 22, 2013 at 17:58 comment added Paul @BRabbit27: Your question says "parabolic", but your comment says "hyperbolic"
Jan 22, 2013 at 17:09 comment added BRabbit27 What I was trying to ask is, if someone ask you "What is the CFL condition for an hyperbolic problem" what would you answer. I mean, I know it is related with the time-step $\Delta t$ and the space-step $\Delta x$. But what's the point? If I make the space-step smaller the approximation on times becomes worse? better? nothing happens? @BrianBorchers It's been a while I took Numerical Analysis and this is the first time reading something about Hyperbolic problems in 1D. Maybe an explanation of stability would help.
Jan 22, 2013 at 15:28 comment added Brian Borchers So your question is "why is this being called a CFL condition when we're not in the finite difference setting of the original CFL condition?"
Jan 22, 2013 at 14:42 comment added Paul A CFL condition is typically stated as a dependence between the temporal step size $\Delta t$ and a spatial step size $\Delta x$. I'm curious where you found this quantity stated as a CFL condition. Could you provide a reference?
Jan 22, 2013 at 14:34 answer added Jed Brown timeline score: 15
Jan 22, 2013 at 13:15 comment added Brian Borchers It isn't at all clear what kind of answer you're asking for. Do you understand what it means for a numerical method to be stable? Do you understand why stability is necessary for a method to be useful in practice? Is there some aspect of the statement or derivation of this stability condition that you don't understand?
Jan 22, 2013 at 10:13 history asked BRabbit27 CC BY-SA 3.0