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Mar 4, 2014 at 4:34 answer added den.run.ai timeline score: 1
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Jan 12, 2012 at 2:45 answer added dmckee --- ex-moderator kitten timeline score: 1
Jan 4, 2012 at 18:48 answer added Barron timeline score: 3
Jan 3, 2012 at 20:35 comment added Dominique It may be useful to specify in what language/environment you model the PDEs. It may restrict the choice of optimizers.
Jan 2, 2012 at 20:29 history edited Geoff Oxberry
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Jan 2, 2012 at 20:01 vote accept Sean Farley
Jan 2, 2012 at 6:16 comment added Geoff Oxberry @JedBrown: That makes sense; it was confusing to see "box constraint" mentioned without, well, an explicit box constraint. For the types of problems you're talking about (design problems, control problems), $u$ is definitely more interesting, but optimization problems are typically stated using the $min$ notation, and their solution sets are described using the $\arg \min$ notation.
Jan 2, 2012 at 5:06 answer added Wolfgang Bangerth timeline score: 4
Jan 2, 2012 at 0:15 comment added Jed Brown It's quite common for $f$ to involve $L^1$ or $W^{1,1}$ regularization, so we should not assume two derivatives.
Jan 2, 2012 at 0:15 comment added Jed Brown $d(u,x) = u$ is one special case, but this more general form is actually common in practice. You can always introduce extra variables if your method can only deal with constraints directly on $u$. We are usually more interested in the value $u$ at which a minimum is attained than in the minimum value of $f$. Sean added the [pde] tag, so you may get some regularity from that. He didn't state whether the system was hyperbolic or not, so let's not assume. Let's not assume that $f$ is convex, since it is often not.
Dec 31, 2011 at 5:57 comment added Geoff Oxberry The edited version does not look like a box-constrained optimization problem. A box-constrained optimization problem would have $a \leq u \leq b$ as a constraint. Is $u$ supposed to be a function of $x$? Is $c$ linear in $u$? If it's not, is it twice-differentiable? Is $f$ convex in $u$? Is it twice-differentiable in $u$? Finally, $\arg \min_{u}$ denotes the set of points in $u$ at which the minimum value of $f$ is attained. Do you mean $\min_{u}$ instead?
Dec 31, 2011 at 5:26 history tweeted twitter.com/#!/StackSciComp/status/152984046933250048
Dec 31, 2011 at 5:05 history edited Jed Brown CC BY-SA 3.0
added 296 characters in body; edited title
Dec 30, 2011 at 20:53 answer added Geoff Oxberry timeline score: 19
Dec 30, 2011 at 20:21 answer added Jungho Lee timeline score: 2
Dec 30, 2011 at 20:18 history asked Sean Farley CC BY-SA 3.0