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Jun 20, 2013 at 22:56 comment added Stefano M In the answer to the follow-up question it turns out that $0.1$ is a dimensional quantity with dimensions $1/\text{time}$. Maybe more consistent results are obtained with $\frac{\alpha}{\Delta t} \cdot (N_t - N_0)$ where $\Delta t$ is the time step?
Jun 18, 2013 at 18:18 vote accept CommunityBot
Jun 18, 2013 at 18:14 answer added user4388 timeline score: 1
Jun 18, 2013 at 18:11 history edited user4388 CC BY-SA 3.0
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May 24, 2013 at 22:30 answer added Nico Schlömer timeline score: 2
May 24, 2013 at 21:48 answer added Bill Greene timeline score: 4
May 24, 2013 at 20:02 history tweeted twitter.com/#!/StackSciComp/status/338022110976954368
May 24, 2013 at 15:57 comment added David Ketcheson The answer is just to use a local error estimate. There is one built in to ODE45, so the easiest thing is to use that, but you could alternatively code up your own.
May 24, 2013 at 13:34 comment added J. M. If memory serves, there should be an option in ode45() that would allow you to retain steps bigger than a certain threshold; you might want to look into that.
May 24, 2013 at 13:29 comment added user4388 Hmm...this could be the problem. The origin of these fixed steps was that somewhere I needed to re-normalize the number of particles before they would all decay away. But maybe I can do this by putting the normalization in odefun and use the "giant time vector". Also, the input $y$ into the ode45 is 4*129*129 numbers. I was afraid if I didn't use time steps I wouldn't have enough memory.
May 24, 2013 at 13:17 review First posts
May 24, 2013 at 15:20
May 24, 2013 at 13:05 comment added J. M. The fundamental problem is that you're forcibly using an adaptive method like ode45() to take equispaced steps. Why, precisely, are you avoiding the generation of the "giant vector"? If you absolutely need equispaced points, have ode45() proceed as usual, and then use interpolation.
May 24, 2013 at 13:01 history asked user4388 CC BY-SA 3.0