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azbri
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can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
What I about know is, that the traction in vertical (y-axis) could be: $$ \vec{t_y} = \sigma_{xy}\vec{e_x} + \sigma_{yy}\vec{e_y} $$ Am I right? Many thanks

Thsi is about traction:
"Note a convention that we have implicitly established: the sense of the force per unit area $t$ across the oblique surface is that the fluid penetrated by the unit normal $n$ acts on the fluid on the other side of the surface. This force per unit area is called the traction across the surface. Note further that $t_x$ indicates the traction across the y − z plane, not the x component of a traction. Representation of components requires a second subscript: $T_{xy}$ is the y component of the traction $t_x$ across the y − z face of the tetrahedron, whereas $T_{xy}$ is the x component of the traction ty across the x − z face. Thus, the first subscript represents the vector component of the force and the second subscript indicates the face on which the force is acting. " But how to compute it?

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
Many thanks

Thsi is about traction:
"Note a convention that we have implicitly established: the sense of the force per unit area $t$ across the oblique surface is that the fluid penetrated by the unit normal $n$ acts on the fluid on the other side of the surface. This force per unit area is called the traction across the surface. Note further that $t_x$ indicates the traction across the y − z plane, not the x component of a traction. Representation of components requires a second subscript: $T_{xy}$ is the y component of the traction $t_x$ across the y − z face of the tetrahedron, whereas $T_{xy}$ is the x component of the traction ty across the x − z face. Thus, the first subscript represents the vector component of the force and the second subscript indicates the face on which the force is acting. " But how to compute it?

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
What I about know is, that the traction in vertical (y-axis) could be: $$ \vec{t_y} = \sigma_{xy}\vec{e_x} + \sigma_{yy}\vec{e_y} $$ Am I right? Many thanks

Thsi is about traction:
"Note a convention that we have implicitly established: the sense of the force per unit area $t$ across the oblique surface is that the fluid penetrated by the unit normal $n$ acts on the fluid on the other side of the surface. This force per unit area is called the traction across the surface. Note further that $t_x$ indicates the traction across the y − z plane, not the x component of a traction. Representation of components requires a second subscript: $T_{xy}$ is the y component of the traction $t_x$ across the y − z face of the tetrahedron, whereas $T_{xy}$ is the x component of the traction ty across the x − z face. Thus, the first subscript represents the vector component of the force and the second subscript indicates the face on which the force is acting. " But how to compute it?

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azbri
  • 73
  • 5

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
Many thanks

Thsi is about traction:
"Note a convention that we have implicitly established: the sense of the force per unit area $t$ across the oblique surface is that the fluid penetrated by the unit normal $n$ acts on the fluid on the other side of the surface. This force per unit area is called the traction across the surface. Note further that $t_x$ indicates the traction across the y − z plane, not the x component of a traction. Representation of components requires a second subscript: $T_{xy}$ is the y component of the traction $t_x$ across the y − z face of the tetrahedron, whereas $T_{xy}$ is the x component of the traction ty across the x − z face. Thus, the first subscript represents the vector component of the force and the second subscript indicates the face on which the force is acting. " But how to compute it?

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
Many thanks

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
Many thanks

Thsi is about traction:
"Note a convention that we have implicitly established: the sense of the force per unit area $t$ across the oblique surface is that the fluid penetrated by the unit normal $n$ acts on the fluid on the other side of the surface. This force per unit area is called the traction across the surface. Note further that $t_x$ indicates the traction across the y − z plane, not the x component of a traction. Representation of components requires a second subscript: $T_{xy}$ is the y component of the traction $t_x$ across the y − z face of the tetrahedron, whereas $T_{xy}$ is the x component of the traction ty across the x − z face. Thus, the first subscript represents the vector component of the force and the second subscript indicates the face on which the force is acting. " But how to compute it?

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azbri
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  • 5

Traction on the boundary - how to compute from velocity field

can you help me? I have a fluid simulation in 2D, where I compute by finite differences on the grid the velocity field and pressure. So this is my output from the program. Now I have to show how the vertical component of traction on the boundary looks like. But I am not sure what the word traction means, what I have to compute. I can compute the stress from the velocity field as

$$ \sigma_{xy}=\eta (\frac{dv_x}{dy}+\frac{dv_y}{dx}) $$

$$ \sigma_{xx}=2\eta \frac{dv_x}{dx} $$

$$ \sigma_{yy}=2\eta \frac{dv_y}{dy} $$

So this I would know how to compute from my results - by finite differences. What does the vertical traction mathematically means, what I have to compute?
Many thanks