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This is a very general question regarding the maximum size of a set of linear equations to be solved by today's fastest hardware, in the form:
$$X = AX + B$$
Where we solve for $X$, and
$A$: $N\times N$ a sparse matrix of floats;
$B$: $N$-vector of floats.
This becomes $X(I-A) = B$ which is best solved using factorization (and not matrix inversion) as I read here.
Do you know or have a reference to a benchmark or paper which gives some maximum value for $N$ with today's fastest hardware? Assume that I can have that hardware, this is a sort of mental what-if exercise. Most benchmarks I have seen use $N < 10000$. I am thinking about $N>10^7$ or more to be processed within a month.
Please consider not only the computational dimension but also storage for $A$. It can be a problem, e.g., assuming $N = 10^6$, storage would be $4\times 10^{12}$ bytes $\approx$ 4 Terabytes for a totally dense matrix, which is about manageable I guess.
Lastly, can the method to solve the system be parallelized so that I can make the assumption that with parallelization $N$ can become pretty large?
later addition to question:
One possible application of this is: consider N products from factories (e.g. screws, an electric motor, an engine, a car). Most products require parts from other products and are used as parts for other more complex products in addition to some quantities ending in the shops - e.g. an electric motor.
For the $i^{th}$ product we have: $X_i = a_{i,1} X_1 + a_{i,2} X_2 + \cdots + a_{i,N} X_N + B_i$ meaning that the quantity of $X_i$ we aim to produce requires $a_{i,1} X_1$ items from product $X_1$, to $N$, plus $B_i$ which is what ends up in shops for general consumption.
Our aim is to find the solution to this problem given final demands ($B$) and "inter-dependancy" quantities $A$.
I guess $A$ is sparse but this probably depends on applications, e.g. Toyota states that a basic car consists of 30,000 other products (all broken down to screws). This is why I mention sparse but I also go for the worst case of "mild-denseness".