How to obtain only the value of my variable using scipy.optimize.minimize

Question

when I minimize a function using scipy.optimize.minimize I get a big list of things as a result, but I would like to only get the value of my variable, this is my code :

import scipy.optimize as so

def func_AC(r):
    return 1/((r**2)+1)

guess = 0

minimo = so.minimize(func_AC,guess)

print(minimo)

and this is what I get:

  fun: array([1.])
  hess_inv: array([[1]])
  jac: array([-1.49011612e-08])
  message: 'Optimization terminated successfully.'
  nfev: 3
  nit: 0
  njev: 1
  status: 0
  success: True
    x: array([0.])

with only this values I would be really happy

success: True
    x: array([0.])

also I need my function to have bounds but I dont know how to, could anybody help me have the same code but with the bound r>=1? thanks in advanced

Answer 1

For the first question, the values are stored in the members of the minimo object. Explicitly

print(minimo.success)
print(minimo.x)

For the second part of the question as to how to setup bounds,

import scipy.optimize as so
from scipy.optimize import Bounds
import numpy as np

my_bounds = Bounds(0,np.inf)

def func_AC(r):
    return 1/((r[0]**2)+1)

guess = [2]

minimo = so.minimize(func_AC,guess,bounds = my_bounds)

print(minimo.success)
print(minimo.x)

The hidden trick here is that scipy optimize likes to have different variables expressed as elements of list. That is the r is no longer a single variable, but rather a list of variables.