New answers tagged


MPI Q1: In a naive implementation yes, you will end up with a copy of the mesh on each process. You can reduce this somewhat by only duplicating the parts of the mesh which contain the surface, since you are only doing a surface integral and not a volume integral. This in theory will reduce how much memory is duplicated per process ($O(n^2)$ vs. $O(n^3)$). I ...

Top 50 recent answers are included